poj 2456 最小值最大化 -电脑资料

    Description

Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a straight line at positions x1,...,xN (0 <= xi <= 1,000,000,000).

    His C (2 <= C <= N) cows don't like this barn layout and become aggressive towards each other once put into a stall. To prevent the cows from hurting each other, FJ want to assign the cows to the stalls, such that the minimum distance between any two of them is as large as possible. What is the largest minimum distance?

    Input

* Line 1: Two space-separated integers: N and C

    * Lines 2..N+1: Line i+1 contains an integer stall location, xi

    Output

* Line 1: One integer: the largest minimum distance

    Sample Input

5 312849

    Sample Output

3

    Hi

/**poj 2456   最小值最大化题目大意：在编号为a0~an的n个点上放m个棋子要求如何防止能使距离最近的两个棋子的距离最大解题思路：二分查找可行的值，贪心：对于每个可行值判断是否能在n个点中挑出m个，
poj 2456  最小值最大化
，
电脑资料
《poj 2456  最小值最大化》(http://meiwen.anslib.com)。          贪心的时候应该注意，我们只要从第一个开始就可以了，如果找不出来那么以第二个以及更后的开始就更找不出来了，因此每次贪心每个点最多考虑          1次，复杂度O(n)*/#include<iostream>#include<stdio.h>#include<string.h>#include using namespace std;const int maxn=100003;int a[maxn];int n,c;bool greed(int x){    int cn=0;    int p=a[0];    for (int i=1; i<n; if="">=p+x)        {            cn++;            p=a[i];        }    }    if (cn>=c-1)        return true ;    return false ;}int main(){    while(~scanf(%d%d ,&n,&c))    {        for(int i=0; i<n; d="" else="" int="" l="0,r=a[n-1],mid;" mid="(l+r)/2;" pre="" r="mid-1;" return="" while=""></n;></n;></string.h></stdio.h></iostream>